Class 12 Physics Chapter 6: Electromagnetic Induction (EMI) | Complete Notes & Derivations

📅 Tuesday, 20 January 2026 📖 3-5 min read
Class 12 Physics • NCERT

Chapter 6: Electromagnetic Induction

Complete Textbook Edition (Theory + Derivations)

Vol 1: Magnetic Flux & Faraday's Laws

In previous chapters, we established that electric current produces a magnetic field. In this chapter, we explore the reverse phenomenon: Can a magnetic field produce electric current? This phenomenon is called Electromagnetic Induction (EMI).

1. Magnetic Flux ($\Phi_B$)

Magnetic Flux is defined as the number of magnetic field lines passing normally through a given surface area.

$$\Phi_B = \vec{B} \cdot \vec{A} = BA \cos \theta$$

Unit: Weber (Wb) or Tesla-meter² ($Tm^2$)
Scalar Quantity

2. Faraday's Laws of Induction

  • First Law: Whenever the magnetic flux linked with a closed circuit changes, an induced EMF (and hence induced current) is produced in it which lasts only so long as the change in flux continues.
  • Second Law: The magnitude of the induced EMF is directly proportional to the time rate of change of magnetic flux.
$$\varepsilon = - \frac{d\Phi_B}{dt}$$
(For a coil of N turns: $\varepsilon = -N \frac{d\Phi_B}{dt}$)

3. Lenz's Law

Statement: The polarity of induced EMF is such that it tends to produce a current which opposes the change in magnetic flux that produced it.

Significance: Lenz's Law is a direct consequence of the Law of Conservation of Energy. Mechanical work done in moving the magnet against the repulsive/attractive force is converted into electrical energy.

Vol 2: Motional EMF & Eddy Currents

1. Motional Electromotive Force

When a conductor moves in a magnetic field, the magnetic Lorentz force acts on its free electrons, creating a potential difference across its ends.

Case A: Translatory Motion (Sliding Rod)
$$\varepsilon = Bvl$$
(Where $B, v, l$ are mutually perpendicular)
Case B: Rotational Motion (Rotating Rod)
A rod of length $l$ rotating with angular velocity $\omega$:

$$\varepsilon = \frac{1}{2} B l^2 \omega$$

2. Eddy Currents

Eddy currents are loops of electrical current induced within bulk conductors by a changing magnetic field in the conductor according to Faraday's law of induction.

Key Concept: Eddy currents flow in closed loops within conductors, in planes perpendicular to the magnetic field. They always oppose the change or motion producing them, in accordance with Lenz's Law.
  • Disadvantages: Unwanted heat generation in transformer cores and electric motors. Minimized by using Laminated Cores.
  • Applications: Magnetic Braking in trains, Induction Furnaces, Electromagnetic Damping (Galvanometers).

Vol 3: Self & Mutual Inductance

1. Self Induction

Definition: The property of a coil by virtue of which it opposes any change in the strength of current flowing through it. It is often called Electrical Inertia.

Formula: $\Phi_B = LI$
Induced EMF: $\varepsilon = -L \frac{dI}{dt}$
Derivation: Self Inductance of a Long Solenoid
For a solenoid of length $l$, area $A$, and number of turns $N$:

$$L = \mu_0 n^2 Al = \frac{\mu_0 N^2 A}{l}$$

2. Mutual Induction

The phenomenon where a changing current in one coil (Primary) induces an EMF in a neighboring coil (Secondary).

Formula: $\Phi_2 = M I_1$
Induced EMF: $\varepsilon_2 = -M \frac{dI_1}{dt}$
Derivation: Mutual Inductance of Two Coaxial Solenoids
$$M = \frac{\mu_0 N_1 N_2 A}{l}$$
(Assuming same length $l$ and Area $A$)

Coefficient of Coupling (K): Measure of how well two coils are magnetically linked. $M = K\sqrt{L_1 L_2}$.

Vol 4: Mission 100 Question Bank

Section A: MCQs

Q1. The SI unit of Magnetic Flux is:
(a) Tesla   (b) Weber   (c) Gauss   (d) Henry
Ans: (b) Weber.

Q2. Lenz's law is a consequence of the law of conservation of:
(a) Charge   (b) Momentum   (c) Energy   (d) Mass
Ans: (c) Energy.


Section B: Numericals (Important)

Q3. A 1.0 m long metal rod rotates about an axis passing through one end with an angular frequency of 400 rad/s in a perpendicular magnetic field of 0.5 T. Calculate the induced EMF.

Solution:
Given: $l = 1.0$ m, $\omega = 400$ rad/s, $B = 0.5$ T.
Formula: $\varepsilon = \frac{1}{2} B \omega l^2$
$\varepsilon = 0.5 \times 0.5 \times 400 \times (1)^2$
$\varepsilon = 0.25 \times 400 = 100$ V.
Ans: 100 Volts.

Q4. Current in a circuit falls from 5.0 A to 0.0 A in 0.1 s. If an average EMF of 200 V is induced, give an estimate of the self-inductance of the circuit.

Solution:
Formula: $|\varepsilon| = L \frac{dI}{dt}$
$200 = L \times \frac{5 - 0}{0.1}$
$200 = L \times 50 \Rightarrow L = 4$ H.
Ans: 4 Henry.

Section C: Conceptual

Q5. Why are the cores of transformers laminated?
Ans: To minimize energy loss due to Eddy Currents. Lamination increases resistance to the path of eddy currents.

Mission 100 Physics Series

Next Chapter: Alternating Current (AC) - The Powerhouse!

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