Class 12 Physics Chapter 8: Electromagnetic Waves (EM Waves) | Spectrum & Notes

📅 Tuesday, 20 January 2026 📖 3-5 min read
Class 12 Physics • NCERT

Chapter 8: Electromagnetic Waves

Complete Textbook Edition (Maxwell's Equations & Spectrum)

Vol 1: Maxwell's Correction & Displacement Current

James Clerk Maxwell unified electricity and magnetism. He noticed an inconsistency in Ampere's Circuital Law and corrected it by introducing the concept of Displacement Current.

1. Displacement Current ($I_d$)

Current is not only the flow of charges. A changing electric field (or flux) also produces a magnetic field. This "equivalent current" is called Displacement Current.

$$I_d = \epsilon_0 \frac{d\Phi_E}{dt}$$

Where $\Phi_E$ is the Electric Flux.

2. Maxwell's Equations (The Unification)

The entire study of electricity and magnetism is summarized in these 4 fundamental equations:

  • Gauss's Law (Electrostatics): $\oint \vec{E} \cdot d\vec{A} = q/\epsilon_0$
  • Gauss's Law (Magnetism): $\oint \vec{B} \cdot d\vec{A} = 0$ (No Monopoles)
  • Faraday's Law: $\oint \vec{E} \cdot d\vec{l} = -d\Phi_B/dt$
  • Ampere-Maxwell Law: $\oint \vec{B} \cdot d\vec{l} = \mu_0 (I_c + I_d)$

Vol 2: Nature & Properties of EM Waves

Source: An accelerated or oscillating charge produces oscillating Electric and Magnetic fields, which regenerate each other and propagate as a wave.

Key Properties

  1. Transverse Nature: $\vec{E}$, $\vec{B}$, and the direction of propagation (velocity $\vec{c}$) are mutually perpendicular.
  2. Speed in Vacuum: They travel with the speed of light ($c = 3 \times 10^8$ m/s).
    $$c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}$$
  3. Relation between E and B: The amplitude of electric and magnetic fields are related by:
    $$c = \frac{E_0}{B_0}$$
  4. No Medium Required: They can travel through vacuum.
  5. Momentum: They carry energy and momentum. If energy $U$ is transferred to a surface in time $t$, total momentum delivered is $p = U/c$.

Vol 3: The Electromagnetic Spectrum

Classification of EM waves based on frequency or wavelength.
Order (Decreasing Wavelength / Increasing Frequency):

Type Production Uses (Important)
Radio Waves Rapid acceleration of electrons in aerials Radio & TV Communication, Cellular Phones.
Microwaves Klystron or Magnetron valves Radar systems (Aircraft navigation), Microwave Ovens.
Infrared (Heat Waves) Hot bodies and molecules Remote controls, Physiotherapy, Haze photography, Greenhouse effect.
Visible Light Electrons moving in atoms Vision, Optical Instruments.
Ultraviolet (UV) Inner shell electrons, Sun Water purification (RO), LASIK eye surgery, Fake currency detection.
X-Rays Bombarding metal with high-energy electrons Medical diagnosis (Fractures), Cancer treatment, Scanning.
Gamma Rays Radioactive decay of nucleus Cancer treatment (Radiotherapy), Nuclear research.

Vol 4: Mission 100 Question Bank

Section A: MCQs

Q1. Which of the following has the minimum wavelength?
(a) Gamma rays   (b) X-rays   (c) Infrared   (d) Microwaves
Ans: (a) Gamma rays (Highest frequency, lowest wavelength).

Q2. The ratio of amplitude of magnetic field to the amplitude of electric field ($E_0/B_0$) for an electromagnetic wave is:
(a) 1   (b) $c$   (c) $1/c$   (d) $\sqrt{\mu_0\epsilon_0}$
Ans: (b) $c$ ($3 \times 10^8$ m/s).


Section B: Numericals & Reasoning

Q3. The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is $B_0 = 510$ nT. What is the amplitude of the electric field part of the wave?

Solution:
Given: $B_0 = 510 \times 10^{-9}$ T, $c = 3 \times 10^8$ m/s.
Formula: $E_0 = c \times B_0$
$E_0 = 3 \times 10^8 \times 510 \times 10^{-9}$
$E_0 = 1530 \times 10^{-1} = 153$ N/C.
Ans: 153 N/C (or V/m).

Q4. Name the electromagnetic waves used in:
(a) Radar systems
(b) Water purification
(c) Remote switches

Answer:
(a) Microwaves (short wavelength allows distinct echoes)
(b) Ultraviolet (UV) rays (kills germs)
(c) Infrared rays

Mission 100 Physics Series

Next Phase: Optics (Ray & Wave) - The Major Scoring Unit!

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