Class 12 Physics Chapter 13: Nuclei | Complete Notes & Radioactivity

📅 Tuesday, 20 January 2026 📖 3-5 min read
Class 12 Physics • NCERT

Chapter 13: Nuclei

Complete Textbook Edition (Binding Energy & Radioactivity)

Vol 1: Nuclear Structure & Mass-Energy

Composition: The nucleus contains Protons (positive) and Neutrons (neutral), collectively known as Nucleons.
Representation: $_Z^A X$
• $Z$ = Atomic Number (No. of Protons)
• $A$ = Mass Number (Total Nucleons = $p + n$)

Einstein's Mass-Energy Equivalence:
Mass is a form of energy. Mass can be converted into energy and vice-versa.

$$E = mc^2$$
Important Conversion:
1 atomic mass unit (1 u) $\approx 931.5$ MeV.

Mass Defect ($\Delta m$)

The mass of a stable nucleus is always less than the sum of the masses of its constituent nucleons. This difference is called Mass Defect.

$$\Delta m = [Z m_p + (A-Z) m_n] - M_{nucleus}$$

Vol 2: Binding Energy Curve & Stability

Binding Energy ($E_b$): The energy released when nucleons bind to form a nucleus (or energy required to separate them). $E_b = \Delta m \times c^2$.

Binding Energy per Nucleon ($E_{bn}$): $E_{bn} = E_b / A$. This determines the stability of a nucleus. Higher $E_{bn}$ means more stability.

Key Features of the Curve:
  • The curve is practically constant ($E_{bn} \approx 8$ MeV) for nuclei with mass number $30 < A < 170$.
  • Maximum Stability: Iron ($^{56}\text{Fe}$) has the highest $E_{bn}$ of about 8.75 MeV.
  • Nuclear Fission: Heavy nuclei ($A > 170$) have lower $E_{bn}$. They split to gain stability.
  • Nuclear Fusion: Light nuclei ($A < 30$) have lower $E_{bn}$. They fuse to gain stability.

Vol 3: Radioactivity & Decay Laws

Radioactivity: Spontaneous emission of radiations ($\alpha, \beta, \gamma$) from an unstable nucleus to achieve stability.

Law of Radioactive Decay

The rate of decay ($dN/dt$) is directly proportional to the number of undecayed nuclei ($N$) present at that instant.

$$\frac{dN}{dt} = -\lambda N$$
$$N = N_0 e^{-\lambda t}$$

($\lambda$ is the Decay Constant)

Half Life & Mean Life

Parameter Formula Relation
Half Life ($T_{1/2}$) $$T_{1/2} = \frac{0.693}{\lambda}$$ Time for $N$ to become $N_0/2$.
Mean Life ($\tau$) $$\tau = \frac{1}{\lambda}$$ $\tau = 1.44 \times T_{1/2}$

Vol 4: Nuclear Energy

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Nuclear Fission

Process of splitting a heavy nucleus into two lighter nuclei.
Reaction: $^{235}\text{U} + n \rightarrow \text{Ba} + \text{Kr} + 3n + Q$
Application: Nuclear Reactors, Atom Bomb.

Nuclear Fusion

Process of combining two light nuclei to form a heavier nucleus.
Reaction: $^2\text{H} + {}^2\text{H} \rightarrow {}^3\text{He} + n + 3.27 \text{ MeV}$
Application: Energy source of Sun & Stars.

Vol 5: Mission 100 Question Bank

Section A: MCQs

Q1. Which of the following has the highest binding energy per nucleon?
(a) Uranium   (b) Helium   (c) Iron   (d) Hydrogen
Ans: (c) Iron ($^{56}\text{Fe}$).

Q2. The SI unit of radioactivity is:
(a) Curie   (b) Rutherford   (c) Becquerel   (d) Roentgen
Ans: (c) Becquerel (Bq).


Section B: Numericals (High Weightage)

Q3. The half-life of a radioactive sample is 10 hours. What fraction of the original sample will remain undecayed after 40 hours?

Solution:
Given: $T_{1/2} = 10$ hrs, $t = 40$ hrs.
Number of half-lives $n = t / T_{1/2} = 40/10 = 4$.
Remaining fraction $N/N_0 = (1/2)^n = (1/2)^4 = 1/16$.
Ans: 1/16th of original sample.

Q4. Calculate the energy released (in MeV) when 1g of matter is converted into energy.

Solution:
Given: $m = 1 \text{ g} = 10^{-3}$ kg, $c = 3 \times 10^8$ m/s.
$E = mc^2 = 10^{-3} \times (3 \times 10^8)^2 = 9 \times 10^{13}$ Joules.
In MeV: $\frac{9 \times 10^{13}}{1.6 \times 10^{-13}} \approx 5.6 \times 10^{26}$ MeV.
Ans: $9 \times 10^{13}$ J.

Mission 100 Physics Series

Next Chapter: Semiconductor Electronics (The Final Chapter!)

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