RBSE Class 12 Physics Electrostatic Potential and Capacitance Complete Notes 2026

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Electrostatic Potential and Capacitance - Class 12 Physics | Chapter 2 NCERT

Electrostatic Potential and Capacitance

स्थिरवैद्युत विभव तथा धारिता | Class 12 Physics - Chapter 2 | NCERT + RBSE 2026

This chapter strictly follows NCERT Class 12 Physics textbook and examination pattern for CBSE, RBSE and other state boards

Subject:Physics
Class:12 (RBSE + NCERT)
Chapter:2
Topic:Electrostatic Potential and Capacitance
Year:2025-26
Status:Complete & Verified
Key Physical Constants & Units:
• Coulomb constant: k = 9 × 10⁹ N·m²/C²
• Permittivity of free space: ε₀ = 8.854 × 10⁻¹² C²/(N·m²)
• Potential unit: 1 V = 1 J/C (Volt = Joule per Coulomb)
• Capacitance unit: 1 F = 1 C/V (Farad = Coulomb per Volt)

Learning Objectives

After completing this chapter, students will be able to:

  • Define electrostatic potential and potential difference between two points
  • Calculate potential due to point charges, dipoles, and systems of charges
  • Understand equipotential surfaces and their relationship with electric field
  • Calculate potential energy of charge systems in various configurations
  • Apply the six fundamental properties of conductors in electrostatic equilibrium
  • Explain dielectric polarisation and its effect on electric field
  • Define capacitance and analyze parallel plate capacitors
  • Solve problems involving series and parallel combinations of capacitors
  • Calculate energy stored in capacitors using multiple equivalent formulas

1. Introduction

Conceptual Framework: From Field to Potential

Chapter 1: Electric Field (Vector quantity)
• Direction matters
• Requires vector addition

Chapter 2: Electric Potential (Scalar quantity)
• Only magnitude
• Algebraic addition
• Simplifies many calculations

Applications: Capacitors, Energy Storage, Circuits

In Chapter 1, we studied electric field and the forces experienced by charges. Now we introduce electrostatic potential, a scalar quantity that provides an alternative and often simpler way to analyze electric phenomena.

This chapter also introduces capacitors, devices that store electric charge and energy, which are fundamental components in electronic circuits, energy storage systems, and modern technology.

2. Electrostatic Potential

Physical Concept: Potential as Work Done

Infinity (V = 0) ←————— Test charge q₀ ————→ Point P

Work done by external force = Wext
Potential at P: V = Wext/q₀

2.1 Definition

Electrostatic potential at a point is defined as the work done per unit positive charge in bringing a test charge from infinity to that point against the electric field.

Electrostatic Potential
V = W/q₀

SI Unit: Volt (V) = Joule/Coulomb (J/C)

Nature: Scalar quantity (can be positive, negative, or zero)

Important Points
  • Potential is a scalar quantity (only magnitude, no direction)
  • Zero of potential is chosen at infinity (V = 0)
  • Potential can be positive (due to +ve charge) or negative (due to −ve charge)
  • Potential difference is independent of the path taken

2.2 Potential Difference

Potential difference between two points A and B is the work done per unit charge in moving a test charge from A to B.

Potential Difference
VAB = VA − VB = WAB/q₀

If VA > VB, positive charge moves naturally from A to B

2.3 Relation Between Electric Field and Potential

Field-Potential Relationship
E = −dV/dr

Or in integral form:

VB − VA = −∫AB E⃗ · dr⃗

Physical Meaning: Electric field points in the direction of maximum decrease of potential. The negative sign indicates that field points from higher to lower potential.

3. Potential Due to a Point Charge

Point Charge Configuration

Charge Q at origin
Point P at distance r

If Q > 0: Potential is positive
If Q < 0: Potential is negative
At r → ∞: V → 0
Potential of Point Charge
V = kQ/r = (1/4πε₀)(Q/r)

where:

  • k = 9 × 10⁹ N·m²/C²
  • Q = charge (can be +ve or −ve)
  • r = distance from charge
  • ε₀ = 8.854 × 10⁻¹² C²/(N·m²)
Sign Convention & Reference
  • Positive charge (Q > 0): V > 0 (positive potential)
  • Negative charge (Q < 0): V < 0 (negative potential)
  • At infinity: V = 0 (reference point)
  • Comparison with field: E = kQ/r² (note: V ∝ 1/r, E ∝ 1/r²)

4. Potential Due to an Electric Dipole

Electric Dipole Configuration

Charges: −q ←—— 2a ——→ +q
Dipole moment: p = q(2a)
Point P at distance r, angle θ

Axial (θ = 0°): V = kp/r²
Equatorial (θ = 90°): V = 0

For a dipole consisting of charges +q and −q separated by distance 2a:

Dipole Potential (for r >> a)
V = (kp cos θ)/r²

where:

  • p = q(2a) = dipole moment
  • θ = angle from dipole axis
  • r = distance from dipole center
Special Cases
  • On axial line (θ = 0° or 180°): V = ±kp/r²
  • On equatorial plane (θ = 90°): V = 0 (equal contributions from +q and −q cancel)
  • Note: Potential falls off as 1/r² (faster than point charge)

5. Potential Due to a System of Charges

Superposition for Potential

Multiple charges: q₁, q₂, q₃, ...
at distances: r₁, r₂, r₃, ...

Total potential = SCALAR SUM
V = V₁ + V₂ + V₃ + ...
(No vector addition needed!)

For a system of multiple point charges, the total potential at any point is the algebraic sum of potentials due to individual charges.

Superposition Principle for Potential
V = V₁ + V₂ + V₃ + ...
V = k(q₁/r₁ + q₂/r₂ + q₃/r₃ + ...)

Key Advantage: Unlike electric field (vector), potentials add algebraically (scalar addition)!

6. Equipotential Surfaces

Equipotential Surface Examples

Point Charge: Concentric spheres
Uniform Field: Parallel planes perpendicular to field
Dipole: Complex 3D surfaces

Key: All points on surface have same V

Equipotential surface is a surface on which electric potential has the same value at all points.

Properties of Equipotential Surfaces
  1. No work is done in moving a charge along an equipotential surface (W = q∆V = 0)
  2. Electric field is always perpendicular to equipotential surface at every point
  3. Equipotential surfaces never intersect each other
  4. For a point charge: equipotential surfaces are concentric spheres
  5. For uniform electric field: equipotential surfaces are parallel planes perpendicular to field
  6. Equipotential surfaces are closer where field is stronger

6.1 Relation Between Field and Potential

Mathematical Relationship
E = −dV/dr

Or equivalently:

VB − VA = −∫AB E⃗ · dr⃗

The negative sign indicates that electric field points in the direction of decreasing potential (from higher V to lower V).

7. Potential Energy of a System of Charges

Building a System of Charges

Bring q₁ from ∞: Work = 0
Bring q₂ from ∞: Work = kq₁q₂/r₁₂
Bring q₃ from ∞: Work = kq₃(q₁/r₁₃ + q₂/r₂₃)

Total PE = Sum of all pair interactions

7.1 Potential Energy of Two Charges

Two Charge System
U = kq₁q₂/r

where r is the separation between charges q₁ and q₂

Sign: U > 0 (repulsive), U < 0 (attractive)

7.2 Potential Energy of Multiple Charges

System of N Charges
U = k Σ (qiqj/rij)

Sum is taken over all distinct pairs (i < j)

8. Potential Energy in an External Field

Types of Potential Energy

1. Self Energy: Interaction between charges in system
2. External Energy: Interaction with external field

Total PE = Self PE + External PE

8.1 Potential Energy of a Single Charge

Single Charge in External Field
U = qV

where V is the potential at the location of charge q due to external sources

8.2 System of Two Charges in External Field

Total potential energy includes both self-energy and interaction with external field:

Two Charges in External Field
U = Uself + Uexternal
U = kq₁q₂/r₁₂ + q₁V₁ + q₂V₂

where V₁ and V₂ are potentials at locations of q₁ and q₂ due to external sources

8.3 Potential Energy of a Dipole in External Field

Dipole in Uniform External Field
U = −pE cos θ

Vector form: U = −p⃗ · E⃗

Energy States of Dipole
  • θ = 0° (aligned with field): U = −pE (minimum, stable equilibrium)
  • θ = 90° (perpendicular): U = 0
  • θ = 180° (opposite to field): U = +pE (maximum, unstable equilibrium)
  • Work to rotate: W = ∆U = pE(cos θ₁ − cos θ₂)

9. Electrostatics of Conductors

Conductor in Electrostatic Equilibrium

Free electrons redistribute instantly

Result: Six Fundamental Properties
1. E = 0 inside
2. Field ⊥ surface
3. Charge on surface only
4. V = constant
5. E = σ/ε₀ at surface
6. Interior shielded

Conductors have six important properties in electrostatic equilibrium:

9.1 Inside a Conductor, Electrostatic Field is Zero

In electrostatic equilibrium, the electric field inside a conductor is zero. Free electrons redistribute themselves on the surface to cancel any internal field.

Consequence

If E ≠ 0 inside, charges would move, contradicting the assumption of electrostatic equilibrium.

9.2 At the Surface, Field Must Be Normal

At the surface of a charged conductor, the electrostatic field must be perpendicular (normal) to the surface at every point.

Reason

If there were a tangential component of E, surface charges would experience a force and would move along the surface, which contradicts equilibrium.

9.3 The Interior Can Have No Excess Charge

In static situation, all excess charge on a conductor resides entirely on its surface. The interior has no net charge.

9.4 Electrostatic Potential is Constant

The electrostatic potential is constant throughout the volume of the conductor and has the same value on its surface as inside.

Constant Potential Property
Vinside = Vsurface = constant

Reason: Since E = 0 inside, no work is done in moving a charge, hence V is constant

9.5 Electric Field at the Surface

Field Just Outside Conductor Surface
E = σ/ε₀

where σ is the surface charge density

Note: This is twice the field of an isolated charged sheet (which is σ/2ε₀)

9.6 Electrostatic Shielding

The interior of a hollow conductor is shielded from external electric fields. External charges induce charges on the outer surface, but the field inside remains zero.

Applications of Electrostatic Shielding
  • Faraday Cage: Metal enclosure protects interior from external fields
  • Coaxial Cables: Outer conductor shields signal from interference
  • Car Protection: Metal body shields passengers during lightning
  • Sensitive Equipment: Enclosed in metal boxes in laboratories

10. Dielectrics and Polarisation

Dielectric in Electric Field

Without Dielectric: E₀, C₀
↓ Insert dielectric
With Dielectric: E = E₀/K, C = KC₀

Field decreases, Capacitance increases
(K = dielectric constant)

Dielectric: An insulating material that, when placed between capacitor plates, increases capacitance.

10.1 Polarisation

When a dielectric is placed in an external electric field, its molecules develop or align dipole moments.

Two Types of Molecules
  • Polar molecules (e.g., H₂O): Have permanent dipole moments that align with external field
  • Non-polar molecules (e.g., N₂): Develop induced dipole moments in external field

Result: Net alignment of dipoles creates an internal field opposing the external field

10.2 Dielectric Constant

Dielectric Constant (Relative Permittivity)
K = εr = E₀/E

Ratio of field without dielectric to field with dielectric

Material Dielectric Constant (K)
Vacuum 1 (exactly)
Air 1.00054 ≈ 1
Paper 3.7
Glass 5-10
Mica 6
Water 80
Properties
  • K ≥ 1 for all materials (K = 1 for vacuum only)
  • Higher K means greater polarisation and greater capacitance increase
  • Dielectrics reduce electric field: E = E₀/K

11. Capacitors and Capacitance

Capacitor Structure

Two conductors (plates)
Separated by insulator

Apply voltage V → Stores charge Q
Capacitance: C = Q/V

Capacitor: A device consisting of two conductors carrying equal and opposite charges, used to store electric charge and energy.

11.1 Definition of Capacitance

Capacitance
C = Q/V

SI Unit: Farad (F) = Coulomb/Volt (C/V)

Understanding Capacitance
  • Capacitance is a measure of ability to store charge
  • 1 Farad is a very large unit (typical capacitors are μF, nF, pF)
  • 1 μF = 10⁻⁶ F, 1 nF = 10⁻⁹ F, 1 pF = 10⁻¹² F
  • Capacitance depends only on geometry and dielectric, not on Q or V

12. The Parallel Plate Capacitor

Parallel Plate Capacitor

Two parallel plates
Area: A
Separation: d
Charge: +Q on one, −Q on other

Field between plates: E = σ/ε₀
Voltage: V = Ed
Capacitance: C = ε₀A/d

The most common type of capacitor consists of two parallel conducting plates of area A separated by distance d.

Parallel Plate Capacitor (Vacuum)
C = ε₀A/d

where:

  • A = area of each plate (m²)
  • d = separation between plates (m)
  • ε₀ = 8.854 × 10⁻¹² F/m
Dependencies
  • C ∝ A: Larger area → more capacitance
  • C ∝ 1/d: Smaller separation → more capacitance
  • Capacitance is independent of charge Q or voltage V

13. Effect of Dielectric on Capacitance

Inserting Dielectric

Before: C₀ = ε₀A/d
↓ Insert dielectric (constant K)
After: C = Kε₀A/d = KC₀

Capacitance increases by factor K

When a dielectric material of dielectric constant K is inserted between the plates:

Parallel Plate with Dielectric
C = Kε₀A/d = KC₀

where C₀ is capacitance without dielectric

Why Capacitance Increases

Dielectric reduces the electric field between plates (E = E₀/K), which reduces the potential difference (V = Ed) for the same charge. Since C = Q/V, capacitance increases.

14. Combination of Capacitors

Two Basic Combinations

SERIES: C₁ —— C₂ —— C₃
• Same Q on all
• Voltages add
• 1/Ceq = 1/C₁ + 1/C₂ + 1/C₃

PARALLEL: C₁ ∥ C₂ ∥ C₃
• Same V on all
• Charges add
• Ceq = C₁ + C₂ + C₃

14.1 Capacitors in Series

Series Combination
1/Ceq = 1/C₁ + 1/C₂ + 1/C₃ + ...

For two capacitors:

Ceq = C₁C₂/(C₁ + C₂)
Properties of Series Combination
  • Same charge Q on all capacitors
  • Voltages add: V = V₁ + V₂ + V₃
  • Equivalent capacitance is less than the smallest individual capacitance
  • Used to increase voltage rating

14.2 Capacitors in Parallel

Parallel Combination
Ceq = C₁ + C₂ + C₃ + ...
Properties of Parallel Combination
  • Same voltage V across all capacitors
  • Charges add: Q = Q₁ + Q₂ + Q₃
  • Equivalent capacitance is greater than the largest individual capacitance
  • Used to increase charge/energy storage capacity
Property Series Parallel
Formula 1/Ceq = Σ(1/Ci) Ceq = ΣCi
Charge (Q) Same on all capacitors Divides: Q = Q₁ + Q₂
Voltage (V) Divides: V = V₁ + V₂ Same on all capacitors
Ceq Less than smallest Greater than largest
Application High voltage rating High capacitance

15. Energy Stored in a Capacitor

Energy Storage Concept

Work done in charging capacitor
= Energy stored in electric field

U = (1/2)QV = (1/2)CV² = (1/2)Q²/C

(All three forms equivalent)
Energy Stored in Capacitor (Three Equivalent Forms)
U = (1/2)QV
U = (1/2)CV²
U = (1/2)Q²/C

Choose form based on given quantities

When to Use Which Formula
  • U = (1/2)QV: When both Q and V are given
  • U = (1/2)CV²: When C and V are given (most common)
  • U = (1/2)Q²/C: When Q and C are given
  • All three give the same answer (they're equivalent)

15.1 Energy Density in Electric Field

Energy Density
u = (1/2)ε₀E²

Unit: J/m³ (Joule per cubic meter)

Energy per unit volume stored in electric field

Practice Questions

Multiple Choice Questions (20 MCQs)

Q1. SI unit of electric potential is:

(a) Joule
(b) Volt
(c) Coulomb
(d) Newton

Answer: (b) Volt
1 Volt = 1 Joule/Coulomb (J/C)

Q2. Potential due to a point charge Q at distance r is:

(a) kQ/r
(b) kQ/r²
(c) kQ/r³
(d) kQr

Answer: (a) kQ/r
V = kQ/r. Compare with electric field E = kQ/r²

Q3. On the equatorial plane of a dipole, potential is:

(a) Maximum
(b) Minimum
(c) Zero
(d) Infinite

Answer: (c) Zero
At θ = 90°, V = (kp cos 90°)/r² = 0

Q4. Work done in moving a charge on an equipotential surface is:

(a) Maximum
(b) Zero
(c) Infinite
(d) Negative

Answer: (b) Zero
W = q∆V = 0 (since ∆V = 0 on equipotential surface)

Q5. Electric field lines and equipotential surfaces are:

(a) Parallel
(b) Perpendicular
(c) At 45°
(d) Can be at any angle

Answer: (b) Perpendicular
Field lines are always perpendicular to equipotential surfaces

Q6. Electric field inside a conductor in electrostatic equilibrium is:

(a) Maximum
(b) Zero
(c) Uniform
(d) Variable

Answer: (b) Zero
First fundamental property of conductors

Q7. Excess charge on a conductor resides:

(a) Throughout volume
(b) Only on surface
(c) At center
(d) Uniformly distributed

Answer: (b) Only on surface
Third property: No excess charge inside conductor

Q8. Potential inside a charged conductor is:

(a) Zero
(b) Constant
(c) Variable
(d) Infinite

Answer: (b) Constant
Fourth property: Vinside = Vsurface = constant

Q9. Electric field just outside a conductor surface is:

(a) σ/2ε₀
(b) σ/ε₀
(c) 2σ/ε₀
(d) Zero

Answer: (b) σ/ε₀
Fifth property: E = σ/ε₀ (perpendicular to surface)

Q10. Dielectric constant K for all materials is:

(a) K < 1
(b) K = 1
(c) K ≥ 1
(d) K ≤ 1

Answer: (c) K ≥ 1
K = 1 only for vacuum, K > 1 for all other materials

Q11. SI unit of capacitance is:

(a) Volt
(b) Coulomb
(c) Farad
(d) Joule

Answer: (c) Farad
1 Farad = 1 Coulomb/Volt (C/V)

Q12. For parallel plate capacitor, C = :

(a) ε₀A/d
(b) ε₀d/A
(c) ε₀Ad
(d) A/ε₀d

Answer: (a) ε₀A/d
C ∝ A (area) and C ∝ 1/d (separation)

Q13. When dielectric is inserted in a capacitor, capacitance:

(a) Decreases
(b) Increases
(c) Remains same
(d) Becomes zero

Answer: (b) Increases
C = KC₀ where K > 1

Q14. In series combination of capacitors:

(a) Q same, V different
(b) V same, Q different
(c) Both same
(d) Both different

Answer: (a) Q same, V different
Charge is same on all, voltages add: V = V₁ + V₂

Q15. Equivalent capacitance in series is:

(a) Greater than largest
(b) Less than smallest
(c) Average of all
(d) Zero

Answer: (b) Less than smallest
1/Ceq = 1/C₁ + 1/C₂ + ... makes Ceq < smallest C

Q16. In parallel combination, Ceq = :

(a) 1/C₁ + 1/C₂
(b) C₁ + C₂
(c) C₁C₂
(d) C₁/C₂

Answer: (b) C₁ + C₂
In parallel: Ceq = C₁ + C₂ + C₃ + ...

Q17. Energy stored in capacitor U = :

(a) QV
(b) (1/2)QV
(c) 2QV
(d) Q/V

Answer: (b) (1/2)QV
Also U = (1/2)CV² = (1/2)Q²/C (all equivalent)

Q18. Relation between E and V is:

(a) E = dV/dr
(b) E = −dV/dr
(c) E = V/r
(d) E = −V/r

Answer: (b) E = −dV/dr
Negative gradient: field points from high to low potential

Q19. Potential energy of dipole in uniform field:

(a) pE cos θ
(b) −pE cos θ
(c) pE sin θ
(d) −pE sin θ

Answer: (b) −pE cos θ
Minimum (−pE) when aligned (θ = 0°)

Q20. Energy density in electric field u = :

(a) ε₀E²
(b) (1/2)ε₀E²
(c) (1/2)ε₀E
(d) ε₀E

Answer: (b) (1/2)ε₀E²
Energy per unit volume in electric field

Formula Sheet

Concept Formula Unit
Potential V = W/q V (Volt)
Point Charge V = kQ/r V
Dipole V = (kp cos θ)/r² V
Potential Difference VAB = VA − VB V
E and V relation E = −dV/dr V/m
PE (two charges) U = kq₁q₂/r J
PE (dipole) U = −pE cos θ J
Field at surface E = σ/ε₀ N/C
Dielectric constant K = E₀/E Dimensionless
Capacitance C = Q/V F (Farad)
Parallel plate C = ε₀A/d F
With dielectric C = KC₀ F
Series 1/Ceq = Σ(1/Ci) F
Parallel Ceq = ΣCi F
Energy (Form 1) U = (1/2)QV J
Energy (Form 2) U = (1/2)CV² J
Energy (Form 3) U = (1/2)Q²/C J
Energy density u = (1/2)ε₀E² J/m³
Chapter Connections

Previous Chapter: Chapter 1 - Electric Charges and Fields (Coulomb's law, Gauss's law, electric field)

Current Chapter: Chapter 2 - Electrostatic Potential and Capacitance (Potential, energy, capacitors)

Next Chapter: Chapter 3 - Current Electricity (Ohm's law, circuits, resistance)

Understanding potential and capacitance builds directly on electric field concepts from Chapter 1 and provides the foundation for analyzing circuits in Chapter 3.

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