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RBSE Class 11 IP Answer Key 2026: 11th Informatics Practices Solved Paper

📅 Tuesday, 3 March 2026 📖 पढ़ रहे हैं...
RBSE Class 11 Informatics Practices Answer Key 2026 | NCERTClasses.com
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RBSE Class 11 Informatics Practices — Model Paper Answer Key 2025-26
Complete Solution | Python + NumPy + SQL | Marking Scheme | Subject Code 04

✅ All MCQ Answers  |  ✅ NumPy Programs  |  ✅ SQL Queries  |  ✅ Python Code  |  ✅ Marking Scheme
📋 Answer Key Details
BoardRBSE, Ajmer
Class11th
SubjectInformatics Practices
Subject Code04
Session2025-26
Theory Marks70
Practical30
MCQ Answers✅ Complete
NumPy Code✅ Full Programs
SQL Queries✅ All Queries

यह RBSE Class 11 Informatics Practices Model Paper 2025-26 की सम्पूर्ण उत्तर कुंजी है। प्रश्न-पत्र के लिए: IP Model Paper PDF →

💡 How to use: Attempt the paper first, then verify. SQL keywords are written in CAPITALS. NumPy programs require import numpy as np at the top. Python indentation = 4 spaces per level.

Section A — Objective Type Questions (20 Marks)

Q.1 — MCQ : Unit 1 & 5 — Computer System + Emerging Trends 4 Marks
Q.1 — All Answers4 × 1 = 4
#QuestionCorrect AnswerReason
(i)Primary memory types(b) RAM, ROM, Cache MemoryAll three are directly accessible by CPU; HDD/SSD are secondary
(ii)Software for specific purpose like Tally(c) Specific Purpose SoftwareTally designed exclusively for accounting — not general use
(iii)Realistic 3D immersive environment via headset(b) Virtual Reality (VR)AR overlays digital on real world; VR = fully simulated environment
(iv)Software over internet on subscription(c) SaaSSoftware as a Service — e.g. Google Docs, Netflix, Tally on Cloud
Q.2 — MCQ : Unit 2 — Python 6 Marks
Q.2 — All Answers6 × 1 = 6
#Code / QuestionCorrect AnswerExplanation
(i)type("3.14")(b) <class 'str'>"3.14" is in quotes → string, not float
(ii)Mutable data type(c) ListLists can be modified; Tuple, String, Integer = immutable
(iii)"JODHPUR"[2:5](a) ODHJ=0,O=1,D=2,H=3,P=4,U=5,R=6 → index 2,3,4 = O,D,H
(iv)len({'a':1,'b':2,'c':3})(b) 3len() on dict returns number of keys = 3
(v)L[-1], L[-2] for L=[10,20,30,40](a) 40 30L[-1]=last=40; L[-2]=second last=30
(vi)Exit a loop immediately(d) breakbreak exits loop; continue skips current iteration; pass does nothing
💡 Q.2(iii) Index chart: J(0) O(1) D(2) H(3) P(4) U(5) R(6) → [2:5] gives index 2,3,4 = DHP... wait: D=2,H=3,P=4 → DHP? No — O=1,D=2,H=3: "JODHPUR"[2:5] = D,H,P = DHP. Rechecking: J(0)O(1)D(2)H(3)P(4)U(5)R(6) → s[2]='D', s[3]='H', s[4]='P' = DHP. Answer corrected: (a) ODH is wrong — correct answer is DHP but since (a) says ODH, none match perfectly — checking again: O=index1, D=index2, H=index3 → [2:5] = D,H,P. In the MCQ options given, closest is (a) ODH which has a typo in the original paper. Write DHP in your answer and explain the index.
Q.3 — MCQ : Unit 3 — NumPy 3 Marks
Q.3 — All Answers3 × 1 = 3
#QuestionCorrect AnswerReason
(i)NumPy function for all-zeros array(c) np.zeros()np.zeros(n) creates array of n zeros; np.ones() → all 1s
(ii)np.arange(2, 10, 3)(a) [2, 5, 8]Start=2, step=3 → 2, 5, 8 (next would be 11 > 10, so stops)
(iii)Attribute giving total number of elements(b) arr.sizesize = total elements | shape = dimensions | ndim = number of axes
Q.4 — MCQ : Unit 4 — SQL 3 Marks
Q.4 — All Answers3 × 1 = 3
#QuestionCorrect AnswerReason
(i)Remove a column from existing table(c) ALTER TABLE ... DROP COLUMNDROP TABLE removes the whole table; ALTER modifies structure
(ii)Filter records based on condition(c) WHEREWHERE = row-level filter; HAVING filters after GROUP BY
(iii)Uniquely identifies each record(d) Primary KeyPK = unique + not null; Candidate key could be PK; FK = reference
Q.5 — Fill in the Blanks 4 Marks
Q.5 — Answers4 × 1 = 4
  • (i) A dictionary stores data in key-value pairs.  e.g. {'name': 'Ravi'}
  • (ii) NumPy function for mean = np.mean()
  • (iii) SQL command to add a new row = INSERT INTO
  • (iv) Field referencing primary key of parent table = Foreign Key
Q.6 — Match the Following 2 Marks
Q.6 — Correct Matches4 × ½ = 2
Column AColumn B
(i) np.concatenate()→ (b)Joins two or more NumPy arrays
(ii) SELECT … FROM … WHERE→ (a)Structured Query Language for data retrieval
(iii) IoT→ (c)Network of physical devices exchanging data
(iv) Blockchain→ (d)Decentralised, immutable digital ledger technology

Section B — Short Answer Type Questions (25 Marks)

Q.7 — Computer System (Unit 1) 2 Marks
Q.7 — Answers2 Marks

(a) Primary vs Secondary Memory

Primary MemorySecondary Memory
Directly accessed by CPUNot directly accessible by CPU
Volatile (RAM) / Non-volatile (ROM)Always non-volatile — data persists
Smaller, faster, costlierLarger, slower, cheaper per GB
e.g. RAM, ROM, Cachee.g. HDD, SSD, USB Drive, DVD

(b) Generic vs Specific Purpose Software

Generic Software is designed for a wide range of general tasks — used by many users across different fields. Example: MS Word, MS Excel, Google Chrome.

Specific Purpose Software is designed to perform one particular task for a specific domain. Example: Tally (accounting), IRCTC (railway booking), hospital management software.

Q.8 — Python Basics 3 Marks
Q.8 — Answers3 Marks

(a) Output + Explanation (2 Marks)

x = 15 y = 4 print(x // y) # Floor division print(x % y) # Modulus (remainder) print(x ** 2) # Exponentiation
3 3 225
  • 15 // 4 = 3 — floor division gives quotient only (15÷4=3.75, floor=3)
  • 15 % 4 = 3 — remainder when 15 is divided by 4 (4×3=12, 15−12=3)
  • 15 ** 2 = 225 — 15 raised to power 2 = 15×15

(b) append() vs extend() (1 Mark)

append()extend()
Adds a single element at the endAdds all elements of an iterable at the end
L=[1,2]; L.append([3,4]) → [1,2,[3,4]]L=[1,2]; L.extend([3,4]) → [1,2,3,4]
Q.9 — Python Control Flow 3 Marks
Q.9 — Program + Output3 Marks

(a) Multiplication Table using for loop (2 Marks)

# Multiplication table of user-entered number n = int(input("Enter a number: ")) for i in range(1, 11): print(n, "×", i, "=", n * i)
Enter a number: 7 7 × 1 = 7 7 × 2 = 14 7 × 3 = 21 ... (up to) 7 × 10 = 70

(b) Output of while loop (1 Mark)

i = 1 while i <= 5: if i % 2 == 0: print(i, end=" ") i += 1
2 4

Loop runs i=1 to 5. Only even values (i%2==0) are printed: 2 and 4. Odd values 1,3,5 are skipped.

Q.10 — Lists & Dictionaries 3 Marks
Q.10 — Answers3 Marks

(a) Dictionary Operations (2 Marks)

student = {'name': 'Ananya', 'age': 16, 'city': 'Jaipur', 'score': 92} # (i) Update score to 95 student['score'] = 95 # (ii) Add new key 'grade' student['grade'] = 'A' # (iii) Delete key 'age' del student['age'] # (iv) Print all key-value pairs using loop for key, value in student.items(): print(key, ":", value)
name : Ananya city : Jaipur score : 95 grade : A

(b) keys() vs values() vs items() (1 Mark)

  • keys() — returns all keys of the dictionary: dict_keys(['name','city',...])
  • values() — returns all values: dict_values(['Ananya','Jaipur',...])
  • items() — returns all key-value pairs as tuples: dict_items([('name','Ananya'),...])
Q.11 — NumPy Basics 3 Marks
Q.11 — Answers3 Marks

(a) NumPy Code Output (2 Marks)

import numpy as np a = np.array([10, 20, 30, 40, 50]) print(a[1:4]) # slicing index 1,2,3 print(a * 2) # element-wise multiply print(np.mean(a)) # arithmetic mean print(np.std(a)) # standard deviation
[20 30 40] [20 40 60 80 100] 30.0 14.142135623730951
  • a[1:4] → elements at index 1,2,3 = [20 30 40]
  • a * 2 → each element ×2 = [20 40 60 80 100]
  • np.mean(a) → (10+20+30+40+50)/5 = 30.0
  • np.std(a) → standard deviation ≈ 14.14

(b) Python List vs NumPy Array (1 Mark)

Python ListNumPy Array
Can hold mixed data typesHolds only one data type (homogeneous)
Slower for mathematical operationsMuch faster — uses C internally
No vectorised operationsSupports element-wise arithmetic directly
Q.12 — NumPy 2D Arrays 3 Marks
Q.12 — Answers3 Marks

(a) 2D Array — shape, size, element access (2 Marks)

import numpy as np # Create 1D array 1-9, reshape to 3x3 arr = np.arange(1, 10).reshape(3, 3) print(arr) print("Shape:", arr.shape) # (3, 3) print("Size:", arr.size) # 9 print("Element [2][3] (1-based):", arr[1][2]) # row2,col3 = 0-based[1][2]
[[1 2 3] [4 5 6] [7 8 9]] Shape: (3, 3) Size: 9 Element at row 2, col 3 = 6
💡 Indexing note: Python uses 0-based indexing. Row 2, Column 3 in exam language = arr[1][2] in Python = 6. Always clarify in exam.

(b) np.zeros(), np.ones(), np.arange() (1 Mark)

  • np.zeros(4) → creates array of 4 zeros: [0. 0. 0. 0.]
  • np.ones((2,3)) → 2×3 array of all ones
  • np.arange(1, 10, 2) → [1, 3, 5, 7, 9] — like Python range but returns NumPy array
Q.13 — SQL Queries on STUDENTS Table 3 Marks
Q.13 — All SQL Queries3 × 1 = 3
📊 Marking: 1 mark each query | Keywords must be in CAPITALS | Semicolon at end recommended

(a) Class 11 students with marks > 80

SELECT SNAME, MARKS FROM STUDENTS WHERE CLASS = 11 AND MARKS > 80;

Result: Priya (91), Sunita (88)

(b) All records in descending order of MARKS

SELECT * FROM STUDENTS ORDER BY MARKS DESC;

Order: Priya(91) → Sunita(88) → Ravi(78) → Rahul(72) → Mohit(65)

(c) SNAME and CITY from Jodhpur or Jaipur

SELECT SNAME, CITY FROM STUDENTS WHERE CITY IN ('Jodhpur', 'Jaipur');

Result: Ravi-Jodhpur, Priya-Jaipur, Mohit-Jodhpur, Rahul-Jaipur

💡 IN operator is shorter than writing CITY='Jodhpur' OR CITY='Jaipur' — both are correct and get full marks.
Q.14 — SQL DDL & DML 3 Marks
Q.14 — Complete SQL Statements3 Marks

(a) CREATE TABLE EMPLOYEE (1½ Marks)

CREATE TABLE EMPLOYEE ( EID INT PRIMARY KEY, ENAME VARCHAR(30), DEPT VARCHAR(20), SALARY FLOAT, DOJ DATE );

(b) INSERT, UPDATE, DELETE (1½ Marks)

-- (i) Insert one record INSERT INTO EMPLOYEE VALUES (101, 'Ramesh Sharma', 'IT', 48000, '2022-06-15'); -- (ii) Update salary to 55000 for EID = 101 UPDATE EMPLOYEE SET SALARY = 55000 WHERE EID = 101; -- (iii) Delete records where DEPT = 'HR' DELETE FROM EMPLOYEE WHERE DEPT = 'HR';
Q.15 — Emerging Trends (any two) 2 Marks
Q.15 — Model Answers (~35 words each)2 × 1 = 2

(a) Artificial Intelligence: AI is the simulation of human intelligence in machines to perform tasks like reasoning, learning, and problem solving. Real-life applications: virtual assistants (Siri, Alexa) and medical diagnosis using AI tools.

(b) Big Data vs Traditional Data: Traditional data is structured, small-scale and easily stored in RDBMS. Big Data is massive, complex, generated at high speed. Three Vs of Big Data: Volume (huge size), Velocity (generated fast), Variety (structured + unstructured).

(c) Blockchain: Blockchain is a decentralised, distributed, and immutable digital ledger that records transactions across multiple computers. No single authority can alter records. Real-life use: Cryptocurrency (Bitcoin, Ethereum) — tracks all financial transactions securely.

Q.16 — Python Program — Even/Odd + Reverse 3 Marks
Q.16 — Complete Program3 Marks
# Accept list, count even/odd, print reverse n = int(input("How many numbers? ")) lst = [] # (a) Accept n integers for i in range(n): num = int(input("Enter number: ")) lst.append(num) # (b) Count even and odd even_count = 0 odd_count = 0 for num in lst: if num % 2 == 0: even_count += 1 else: odd_count += 1 print("Even numbers:", even_count) print("Odd numbers:", odd_count) # (c) Print in reverse without reverse() print("Reversed list:") for i in range(n-1, -1, -1): print(lst[i], end=" ")
How many numbers? 5 Enter number: 3 7 4 8 5 Even numbers: 2 Odd numbers: 3 Reversed list: 5 8 4 7 3

Section C — Long Answer Type Questions (25 Marks)

Q.17 — Python Data Types + String Program 5 Marks
Q.17 — Option A: Data Types + Palindrome5 Marks
📊 Marking: Part (a) = 3 marks (1 each) | Part (b) = 2 marks

(a-i) List

# List — ordered, mutable, allows duplicates fruits = ["apple", "mango", "banana", "mango"] print(fruits[0]) # indexing → apple fruits.append("grape") # built-in: append fruits.sort() # built-in: sort

(a-ii) Tuple

# Tuple — ordered, immutable, faster than list coords = (26.9, 75.8) # lat/long — shouldn't change print(coords[0]) # indexing → 26.9 print(coords.count(26.9)) # built-in: count print(coords.index(75.8)) # built-in: index

Preferred when: data is fixed/constant (days of week, RGB values, GPS coords).

(a-iii) Dictionary

# Dictionary — key-value pairs, mutable, unordered emp = {'id': 101, 'name': 'Amit', 'salary': 45000} print(emp['name']) # accessing → Amit print(emp.keys()) # built-in: keys print(emp.values()) # built-in: values

(b) Count Vowels + Palindrome Check (2 Marks)

# Count vowels and check palindrome s = input("Enter a string: ").lower() # Count vowels vowels = "aeiou" count = sum(1 for ch in s if ch in vowels) print("Total vowels:", count) # Check palindrome if s == s[::-1]: print(s, "is a Palindrome") else: print(s, "is NOT a Palindrome")
Enter a string: madam Total vowels: 2 madam is a Palindrome Enter a string: hello Total vowels: 2 hello is NOT a Palindrome
Q.17 — Option B: Mutable/Immutable + Second Largest5 Marks

(a-i) Mutable vs Immutable

Mutable = can be changed after creation. Example: L=[1,2,3]; L[0]=10 → L=[10,2,3] ✅

Immutable = cannot be changed. Example: T=(1,2,3); T[0]=10TypeError

Mutable types: List, Dictionary, Set | Immutable: Integer, Float, String, Tuple

(a-ii) Type Conversion

  • Implicit: Python automatically converts — x = 5 + 2.0 → x = 7.0 (int auto-promoted to float)
  • Explicit: Programmer manually converts — x = int("42") → x = 42 (string to int)

(a-iii) is / is not vs ==

  • == checks value equality — are the values same ?
  • is checks identity — do they point to the same object in memory ?
a = [1,2]; b = [1,2] print(a == b) # True — same values print(a is b) # False — different objects in memory

(b) Second Largest without max()/sort() (2 Marks)

n = int(input("How many numbers? ")) lst = [] for i in range(n): lst.append(int(input("Enter: "))) first = second = float('-inf') for num in lst: if num > first: second = first first = num elif num > second and num != first: second = num print("Second largest:", second)
List: [10, 45, 23, 67, 34] Second largest: 45
Q.18 — NumPy Arrays — 1D, 2D, Operations 5 Marks
Q.18 — Complete NumPy Programs5 Marks
📊 Marking: Part (a) = 3 marks | Part (b) = 2 marks

(a) 1D → Reshape → Index (3 Marks)

import numpy as np # (i) 1D array 1 to 20 using arange arr = np.arange(1, 21) print("Array:", arr) print("Shape:", arr.shape) # (20,) print("Size:", arr.size) # 20 print("Dtype:", arr.dtype) # int64 # (ii) Reshape to 4×5 arr2d = arr.reshape(4, 5) print("\nReshaped 4×5 array:\n", arr2d) # (iii) Indexing the 2D array print("\nSecond row (index 1):", arr2d[1]) # [6 7 8 9 10] print("Last column:", arr2d[:, -1]) # [ 5 10 15 20] print("Element at [2][3] (0-based):", arr2d[2][3]) # 19
Array: [ 1 2 3 ... 20] Shape: (20,) Size: 20 Dtype: int64 Reshaped 4×5 array: [[ 1 2 3 4 5] [ 6 7 8 9 10] [11 12 13 14 15] [16 17 18 19 20]] Second row: [ 6 7 8 9 10] Last column: [ 5 10 15 20] Element at [2][3] = 14

(b) Array Operations — A and B (2 Marks)

import numpy as np A = np.array([5, 10, 15, 20]) B = np.array([2, 4, 6, 8]) print("Element-wise sum:", A + B) # [7 14 21 28] print("Element-wise product:", A * B) # [10 40 90 160] C = np.concatenate((A, B)) print("Concatenated:", C) # [ 5 10 15 20 2 4 6 8] print("Mean of C:", np.mean(C)) # 8.75 print("Std dev of A:", np.std(A)) # 5.59...
Element-wise sum: [ 7 14 21 28] Element-wise product: [10 40 90 160] Concatenated: [ 5 10 15 20 2 4 6 8] Mean of C: 8.75 Std dev of A: 5.590169943749474
Q.19 — SQL Queries on PRODUCTS Table 5 Marks
Q.19 — Option A: All SQL Queries5 × 1 = 5
📊 Marking: 1 mark each correct query | Alternate correct syntax also accepted

(a) Electronics with price between 1000–20000

SELECT * FROM PRODUCTS WHERE CATEGORY = 'Electronics' AND PRICE BETWEEN 1000 AND 20000;

Result: Mobile (18000), Headphones (2500), Keyboard (1200)

(b) Most expensive product per category

SELECT CATEGORY, PNAME, MAX(PRICE) AS MAX_PRICE FROM PRODUCTS GROUP BY CATEGORY;

Electronics → Laptop 45000 | Furniture → Table 7500

(c) Products with 'a' anywhere in name

SELECT PNAME FROM PRODUCTS WHERE PNAME LIKE '%a%';

Result: Laptop, Chair, Table, Headphones, Keyboard

(d) Update Mobile price + increase Furniture stock

-- Update Mobile price UPDATE PRODUCTS SET PRICE = 20000 WHERE PNAME = 'Mobile'; -- Increase Furniture stock by 10 UPDATE PRODUCTS SET STOCK = STOCK + 10 WHERE CATEGORY = 'Furniture';

(e) Total stock and average price per category

SELECT CATEGORY, SUM(STOCK) AS TOTAL_STOCK, AVG(PRICE) AS AVG_PRICE FROM PRODUCTS GROUP BY CATEGORY;
CATEGORY | TOTAL_STOCK | AVG_PRICE Electronics | 205 | 17175.0 Furniture | 70 | 5500.0
💡 GROUP BY tip: Whenever you use aggregate functions (SUM, AVG, MAX, COUNT) with a non-aggregate column, you must use GROUP BY that column. Very common exam question.
Q.19 — Option B: CREATE DB + DDL + DML5 Marks

(a) Part (i)–(v) SQL Statements

-- (i) Create and use database CREATE DATABASE SCHOOL; USE SCHOOL; -- (ii) Create TEACHER table CREATE TABLE TEACHER ( TID INT PRIMARY KEY, TNAME VARCHAR(40) NOT NULL, SUBJECT VARCHAR(30), SALARY FLOAT, EXPERIENCE INT ); -- (iii) Add column PHONE using ALTER ALTER TABLE TEACHER ADD PHONE VARCHAR(15); -- (iv) Drop column PHONE ALTER TABLE TEACHER DROP COLUMN PHONE; -- (v) Teachers with experience > 5, order by salary desc SELECT TNAME, SALARY FROM TEACHER WHERE EXPERIENCE > 5 ORDER BY SALARY DESC;

(b) DDL vs DML (2 Marks)

DDL — Data Definition LanguageDML — Data Manipulation Language
Defines structure/schema of databaseManipulates data within the tables
Commands: CREATE, DROP, ALTER, TRUNCATECommands: INSERT, UPDATE, DELETE, SELECT
Cannot be rolled back easilyCan be rolled back (transactional)
Q.20 — Python Functions + Dictionary 5 Marks
Q.20 — Complete Programs5 Marks
📊 Marking: Part (a) = 3 marks | Part (b) = 2 marks

(a) statistics_summary() — Mean, Median, Mode without module (3 Marks)

# Mean, Median, Mode — without statistics module def statistics_summary(data): n = len(data) # Mean mean = sum(data) / n # Median s = sorted(data) mid = n // 2 median = s[mid] if n % 2 != 0 else (s[mid-1] + s[mid]) / 2 # Mode — element with highest frequency freq = {} for item in data: freq[item] = freq.get(item, 0) + 1 mode = max(freq, key=freq.get) return mean, median, mode # Test with given data data = [4, 8, 6, 5, 3, 8, 2, 8, 6, 4] m, med, mod = statistics_summary(data) print("Mean:", m) print("Median:", med) print("Mode:", mod)
Mean: 5.4 Median: 5.5 Mode: 8

Verification: Sum=54, n=10 → Mean=5.4 | Sorted=[2,3,4,4,5,6,6,8,8,8] → Median=(5+6)/2=5.5 | 8 appears 3 times → Mode=8 ✅

(b) Character Frequency of "RAJASTHAN" using while loop + dict (2 Marks)

s = "RAJASTHAN" freq = {} i = 0 while i < len(s): ch = s[i] if ch in freq: freq[ch] += 1 else: freq[ch] = 1 i += 1 for ch, count in freq.items(): print(ch, ":", count)
R : 1 A : 3 J : 1 S : 1 T : 1 H : 1 N : 1
Q.21 — NumPy 2D Operations + DBMS / Emerging Trends 5 Marks
Q.21 — Option A: NumPy 2D + Relational Model5 Marks

(a) 2D Array Operations (3 Marks)

import numpy as np # (i) Create two 3×3 arrays X = np.array([[1, 3, 5], [2, 4, 6], [7, 8, 9]]) Y = np.array([[9, 8, 7], [6, 5, 4], [3, 2, 1]]) # (ii) Matrix addition and element-wise product print("X + Y:\n", X + Y) print("X * Y (element-wise):\n", X * Y) # (iii) Boolean indexing — elements > 5 print("Elements of X > 5:", X[X > 5]) # (iv) Statistics on X print("Max:", np.max(X)) print("Min:", np.min(X)) print("Sum:", np.sum(X)) print("Mean:", np.mean(X)) print("Variance:", np.var(X))
X + Y: [[10 11 12] [ 8 9 10] [10 10 10]] X * Y (element-wise): [[ 9 24 35] [12 20 24] [21 16 9]] Elements of X > 5: [7 8 9] Max: 9 Min: 1 Sum: 45 Mean: 5.0 Variance: 6.888...

(b) Relational Data Model Terms (2 Marks)

TermDefinitionExample
TupleA single row/record in a tableOne student's complete record
AttributeA column representing a propertySID, SNAME, MARKS
DomainSet of valid values an attribute can holdMARKS domain: 0 to 100 (integer)
Primary KeyAttribute that uniquely identifies each tupleSID in STUDENTS table
Foreign KeyAttribute referencing primary key of another tableSID in MARKS table → references STUDENTS.SID
Q.21 — Option B: Emerging Trends + NumPy Random5 Marks

(a) Emerging Trends (3 Marks)

(i) Natural Language Processing (NLP): NLP is a branch of AI that enables computers to understand, interpret, and generate human language. Examples: Google Translate (translates between languages), Chatbots and virtual assistants (Siri, Alexa understand spoken commands).

(ii) Grid Computing vs Cloud Computing:

Grid ComputingCloud Computing
Distributed computing using multiple connected systems for one taskOn-demand computing resources over the internet
Resources are heterogeneous and geographically dispersedCentrally managed, scalable resources
Used for scientific computing (weather, genome research)Used for web services, storage, apps (AWS, GCP)

(iii) Smart Cities: Smart cities use technology to improve infrastructure, governance, and quality of life. Technologies: (1) IoT sensors for traffic management, (2) AI-based surveillance for security, (3) Cloud computing for centralised data management and government services.

(b) NumPy Random Array Program (2 Marks)

import numpy as np # (i) Create array of 10 random integers between 1 and 50 arr = np.random.randint(1, 51, 10) print("Array:", arr) # (ii) Elements divisible by 5 print("Divisible by 5:", arr[arr % 5 == 0]) # (iii) Replace elements < 20 with 0 arr[arr < 20] = 0 print("Final array:", arr)
Array: [34 7 45 12 50 18 25 3 40 16] Divisible by 5: [45 50 25 40] Final array: [34 0 45 0 50 0 25 0 40 0]
💡 Boolean indexing: arr[arr % 5 == 0] — condition inside square brackets selects only elements satisfying the condition. arr[condition] = 0 replaces those elements. This is one of the most important NumPy exam topics.

Marking Scheme Summary

📊 Complete Marks DistributionTheory 70 Marks
SectionQuestionsTopicsMarks
AQ.1–6MCQ + Fill Blanks + Match (Unit 1–5)20
BQ.7–16Computer System + Python + NumPy + SQL + Trends25
CQ.17–21Long Programs + Queries + DBMS concepts25
Theory Total70
Practical (Python 8 + NumPy 5 + SQL 5 + File 7 + Viva 5)30
Grand Total100
💡 Score More — IP Golden Rules:
  • SQL: Write all keywords in CAPITALS. Always end with semicolon. Mention column names explicitly — SELECT * gets fewer marks than named columns.
  • NumPy: Always write import numpy as np first. Show output after each print statement if asked.
  • Python: Indentation = 4 spaces. Write comments — examiners reward documented code.
  • GROUP BY: Whenever aggregate function (SUM, AVG, MAX) is used with another column → GROUP BY is mandatory.
  • LIKE operator: % = any number of characters | _ = exactly one character. Very common in exam.

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