📋 Answer Key Details
| Board | RBSE, Ajmer |
| Class | 11th |
| Subject | Informatics Practices |
| Subject Code | 04 |
| Session | 2025-26 |
| Theory Marks | 70 |
| Practical | 30 |
| MCQ Answers | ✅ Complete |
| NumPy Code | ✅ Full Programs |
| SQL Queries | ✅ All Queries |
यह RBSE Class 11 Informatics Practices Model Paper 2025-26 की सम्पूर्ण उत्तर कुंजी है। प्रश्न-पत्र के लिए: IP Model Paper PDF →
💡 How to use: Attempt the paper first, then verify. SQL keywords are written in CAPITALS. NumPy programs require import numpy as np at the top. Python indentation = 4 spaces per level.
Section A — Objective Type Questions (20 Marks)
Q.1 — MCQ : Unit 1 & 5 — Computer System + Emerging Trends 4 Marks
Q.1 — All Answers4 × 1 = 4
| # | Question | Correct Answer | Reason |
| (i) | Primary memory types | (b) RAM, ROM, Cache Memory | All three are directly accessible by CPU; HDD/SSD are secondary |
| (ii) | Software for specific purpose like Tally | (c) Specific Purpose Software | Tally designed exclusively for accounting — not general use |
| (iii) | Realistic 3D immersive environment via headset | (b) Virtual Reality (VR) | AR overlays digital on real world; VR = fully simulated environment |
| (iv) | Software over internet on subscription | (c) SaaS | Software as a Service — e.g. Google Docs, Netflix, Tally on Cloud |
Q.2 — MCQ : Unit 2 — Python 6 Marks
Q.2 — All Answers6 × 1 = 6
| # | Code / Question | Correct Answer | Explanation |
| (i) | type("3.14") | (b) <class 'str'> | "3.14" is in quotes → string, not float |
| (ii) | Mutable data type | (c) List | Lists can be modified; Tuple, String, Integer = immutable |
| (iii) | "JODHPUR"[2:5] | (a) ODH | J=0,O=1,D=2,H=3,P=4,U=5,R=6 → index 2,3,4 = O,D,H |
| (iv) | len({'a':1,'b':2,'c':3}) | (b) 3 | len() on dict returns number of keys = 3 |
| (v) | L[-1], L[-2] for L=[10,20,30,40] | (a) 40 30 | L[-1]=last=40; L[-2]=second last=30 |
| (vi) | Exit a loop immediately | (d) break | break exits loop; continue skips current iteration; pass does nothing |
💡 Q.2(iii) Index chart: J(0) O(1) D(2) H(3) P(4) U(5) R(6) → [2:5] gives index 2,3,4 = DHP... wait: D=2,H=3,P=4 → DHP? No — O=1,D=2,H=3: "JODHPUR"[2:5] = D,H,P = DHP. Rechecking: J(0)O(1)D(2)H(3)P(4)U(5)R(6) → s[2]='D', s[3]='H', s[4]='P' = DHP. Answer corrected: (a) ODH is wrong — correct answer is DHP but since (a) says ODH, none match perfectly — checking again: O=index1, D=index2, H=index3 → [2:5] = D,H,P. In the MCQ options given, closest is (a) ODH which has a typo in the original paper. Write DHP in your answer and explain the index.
Q.3 — MCQ : Unit 3 — NumPy 3 Marks
Q.3 — All Answers3 × 1 = 3
| # | Question | Correct Answer | Reason |
| (i) | NumPy function for all-zeros array | (c) np.zeros() | np.zeros(n) creates array of n zeros; np.ones() → all 1s |
| (ii) | np.arange(2, 10, 3) | (a) [2, 5, 8] | Start=2, step=3 → 2, 5, 8 (next would be 11 > 10, so stops) |
| (iii) | Attribute giving total number of elements | (b) arr.size | size = total elements | shape = dimensions | ndim = number of axes |
Q.4 — MCQ : Unit 4 — SQL 3 Marks
Q.4 — All Answers3 × 1 = 3
| # | Question | Correct Answer | Reason |
| (i) | Remove a column from existing table | (c) ALTER TABLE ... DROP COLUMN | DROP TABLE removes the whole table; ALTER modifies structure |
| (ii) | Filter records based on condition | (c) WHERE | WHERE = row-level filter; HAVING filters after GROUP BY |
| (iii) | Uniquely identifies each record | (d) Primary Key | PK = unique + not null; Candidate key could be PK; FK = reference |
Q.5 — Fill in the Blanks 4 Marks
Q.5 — Answers4 × 1 = 4
- (i) A dictionary stores data in key-value pairs. e.g. {'name': 'Ravi'}
- (ii) NumPy function for mean = np.mean()
- (iii) SQL command to add a new row = INSERT INTO
- (iv) Field referencing primary key of parent table = Foreign Key
Q.6 — Match the Following 2 Marks
Q.6 — Correct Matches4 × ½ = 2
| Column A | → | Column B |
| (i) np.concatenate() | → (b) | Joins two or more NumPy arrays |
| (ii) SELECT … FROM … WHERE | → (a) | Structured Query Language for data retrieval |
| (iii) IoT | → (c) | Network of physical devices exchanging data |
| (iv) Blockchain | → (d) | Decentralised, immutable digital ledger technology |
Section B — Short Answer Type Questions (25 Marks)
Q.7 — Computer System (Unit 1) 2 Marks
Q.7 — Answers2 Marks
(a) Primary vs Secondary Memory
| Primary Memory | Secondary Memory |
| Directly accessed by CPU | Not directly accessible by CPU |
| Volatile (RAM) / Non-volatile (ROM) | Always non-volatile — data persists |
| Smaller, faster, costlier | Larger, slower, cheaper per GB |
| e.g. RAM, ROM, Cache | e.g. HDD, SSD, USB Drive, DVD |
(b) Generic vs Specific Purpose Software
Generic Software is designed for a wide range of general tasks — used by many users across different fields. Example: MS Word, MS Excel, Google Chrome.
Specific Purpose Software is designed to perform one particular task for a specific domain. Example: Tally (accounting), IRCTC (railway booking), hospital management software.
Q.8 — Python Basics 3 Marks
Q.8 — Answers3 Marks
(a) Output + Explanation (2 Marks)
x = 15
y = 4
print(x // y) # Floor division
print(x % y) # Modulus (remainder)
print(x ** 2) # Exponentiation
3
3
225
15 // 4 = 3 — floor division gives quotient only (15÷4=3.75, floor=3)
15 % 4 = 3 — remainder when 15 is divided by 4 (4×3=12, 15−12=3)
15 ** 2 = 225 — 15 raised to power 2 = 15×15
(b) append() vs extend() (1 Mark)
| append() | extend() |
| Adds a single element at the end | Adds all elements of an iterable at the end |
L=[1,2]; L.append([3,4]) → [1,2,[3,4]] | L=[1,2]; L.extend([3,4]) → [1,2,3,4] |
Q.9 — Python Control Flow 3 Marks
Q.9 — Program + Output3 Marks
(a) Multiplication Table using for loop (2 Marks)
# Multiplication table of user-entered number
n = int(input("Enter a number: "))
for i in range(1, 11):
print(n, "×", i, "=", n * i)
Enter a number: 7
7 × 1 = 7
7 × 2 = 14
7 × 3 = 21
... (up to)
7 × 10 = 70
(b) Output of while loop (1 Mark)
i = 1
while i <= 5:
if i % 2 == 0:
print(i, end=" ")
i += 1
2 4
Loop runs i=1 to 5. Only even values (i%2==0) are printed: 2 and 4. Odd values 1,3,5 are skipped.
Q.10 — Lists & Dictionaries 3 Marks
Q.10 — Answers3 Marks
(a) Dictionary Operations (2 Marks)
student = {'name': 'Ananya', 'age': 16, 'city': 'Jaipur', 'score': 92}
# (i) Update score to 95
student['score'] = 95
# (ii) Add new key 'grade'
student['grade'] = 'A'
# (iii) Delete key 'age'
del student['age']
# (iv) Print all key-value pairs using loop
for key, value in student.items():
print(key, ":", value)
name : Ananya
city : Jaipur
score : 95
grade : A
(b) keys() vs values() vs items() (1 Mark)
keys() — returns all keys of the dictionary: dict_keys(['name','city',...])
values() — returns all values: dict_values(['Ananya','Jaipur',...])
items() — returns all key-value pairs as tuples: dict_items([('name','Ananya'),...])
Q.11 — NumPy Basics 3 Marks
Q.11 — Answers3 Marks
(a) NumPy Code Output (2 Marks)
import numpy as np
a = np.array([10, 20, 30, 40, 50])
print(a[1:4]) # slicing index 1,2,3
print(a * 2) # element-wise multiply
print(np.mean(a)) # arithmetic mean
print(np.std(a)) # standard deviation
[20 30 40]
[20 40 60 80 100]
30.0
14.142135623730951
a[1:4] → elements at index 1,2,3 = [20 30 40]
a * 2 → each element ×2 = [20 40 60 80 100]
np.mean(a) → (10+20+30+40+50)/5 = 30.0
np.std(a) → standard deviation ≈ 14.14
(b) Python List vs NumPy Array (1 Mark)
| Python List | NumPy Array |
| Can hold mixed data types | Holds only one data type (homogeneous) |
| Slower for mathematical operations | Much faster — uses C internally |
| No vectorised operations | Supports element-wise arithmetic directly |
Q.12 — NumPy 2D Arrays 3 Marks
Q.12 — Answers3 Marks
(a) 2D Array — shape, size, element access (2 Marks)
import numpy as np
# Create 1D array 1-9, reshape to 3x3
arr = np.arange(1, 10).reshape(3, 3)
print(arr)
print("Shape:", arr.shape) # (3, 3)
print("Size:", arr.size) # 9
print("Element [2][3] (1-based):", arr[1][2]) # row2,col3 = 0-based[1][2]
[[1 2 3]
[4 5 6]
[7 8 9]]
Shape: (3, 3)
Size: 9
Element at row 2, col 3 = 6
💡 Indexing note: Python uses 0-based indexing. Row 2, Column 3 in exam language = arr[1][2] in Python = 6. Always clarify in exam.
(b) np.zeros(), np.ones(), np.arange() (1 Mark)
np.zeros(4) → creates array of 4 zeros: [0. 0. 0. 0.]
np.ones((2,3)) → 2×3 array of all ones
np.arange(1, 10, 2) → [1, 3, 5, 7, 9] — like Python range but returns NumPy array
Q.13 — SQL Queries on STUDENTS Table 3 Marks
Q.13 — All SQL Queries3 × 1 = 3
📊 Marking: 1 mark each query | Keywords must be in CAPITALS | Semicolon at end recommended
(a) Class 11 students with marks > 80
SELECT SNAME, MARKS
FROM STUDENTS
WHERE CLASS = 11 AND MARKS > 80;
Result: Priya (91), Sunita (88)
(b) All records in descending order of MARKS
SELECT *
FROM STUDENTS
ORDER BY MARKS DESC;
Order: Priya(91) → Sunita(88) → Ravi(78) → Rahul(72) → Mohit(65)
(c) SNAME and CITY from Jodhpur or Jaipur
SELECT SNAME, CITY
FROM STUDENTS
WHERE CITY IN ('Jodhpur', 'Jaipur');
Result: Ravi-Jodhpur, Priya-Jaipur, Mohit-Jodhpur, Rahul-Jaipur
💡 IN operator is shorter than writing CITY='Jodhpur' OR CITY='Jaipur' — both are correct and get full marks.
Q.14 — SQL DDL & DML 3 Marks
Q.14 — Complete SQL Statements3 Marks
(a) CREATE TABLE EMPLOYEE (1½ Marks)
CREATE TABLE EMPLOYEE (
EID INT PRIMARY KEY,
ENAME VARCHAR(30),
DEPT VARCHAR(20),
SALARY FLOAT,
DOJ DATE
);
(b) INSERT, UPDATE, DELETE (1½ Marks)
-- (i) Insert one record
INSERT INTO EMPLOYEE VALUES (101, 'Ramesh Sharma', 'IT', 48000, '2022-06-15');
-- (ii) Update salary to 55000 for EID = 101
UPDATE EMPLOYEE
SET SALARY = 55000
WHERE EID = 101;
-- (iii) Delete records where DEPT = 'HR'
DELETE FROM EMPLOYEE
WHERE DEPT = 'HR';
Q.15 — Emerging Trends (any two) 2 Marks
Q.15 — Model Answers (~35 words each)2 × 1 = 2
(a) Artificial Intelligence: AI is the simulation of human intelligence in machines to perform tasks like reasoning, learning, and problem solving. Real-life applications: virtual assistants (Siri, Alexa) and medical diagnosis using AI tools.
(b) Big Data vs Traditional Data: Traditional data is structured, small-scale and easily stored in RDBMS. Big Data is massive, complex, generated at high speed. Three Vs of Big Data: Volume (huge size), Velocity (generated fast), Variety (structured + unstructured).
(c) Blockchain: Blockchain is a decentralised, distributed, and immutable digital ledger that records transactions across multiple computers. No single authority can alter records. Real-life use: Cryptocurrency (Bitcoin, Ethereum) — tracks all financial transactions securely.
Q.16 — Python Program — Even/Odd + Reverse 3 Marks
Q.16 — Complete Program3 Marks
# Accept list, count even/odd, print reverse
n = int(input("How many numbers? "))
lst = []
# (a) Accept n integers
for i in range(n):
num = int(input("Enter number: "))
lst.append(num)
# (b) Count even and odd
even_count = 0
odd_count = 0
for num in lst:
if num % 2 == 0:
even_count += 1
else:
odd_count += 1
print("Even numbers:", even_count)
print("Odd numbers:", odd_count)
# (c) Print in reverse without reverse()
print("Reversed list:")
for i in range(n-1, -1, -1):
print(lst[i], end=" ")
How many numbers? 5
Enter number: 3 7 4 8 5
Even numbers: 2
Odd numbers: 3
Reversed list: 5 8 4 7 3
Section C — Long Answer Type Questions (25 Marks)
Q.17 — Python Data Types + String Program 5 Marks
Q.17 — Option A: Data Types + Palindrome5 Marks
📊 Marking: Part (a) = 3 marks (1 each) | Part (b) = 2 marks
(a-i) List
# List — ordered, mutable, allows duplicates
fruits = ["apple", "mango", "banana", "mango"]
print(fruits[0]) # indexing → apple
fruits.append("grape") # built-in: append
fruits.sort() # built-in: sort
(a-ii) Tuple
# Tuple — ordered, immutable, faster than list
coords = (26.9, 75.8) # lat/long — shouldn't change
print(coords[0]) # indexing → 26.9
print(coords.count(26.9)) # built-in: count
print(coords.index(75.8)) # built-in: index
Preferred when: data is fixed/constant (days of week, RGB values, GPS coords).
(a-iii) Dictionary
# Dictionary — key-value pairs, mutable, unordered
emp = {'id': 101, 'name': 'Amit', 'salary': 45000}
print(emp['name']) # accessing → Amit
print(emp.keys()) # built-in: keys
print(emp.values()) # built-in: values
(b) Count Vowels + Palindrome Check (2 Marks)
# Count vowels and check palindrome
s = input("Enter a string: ").lower()
# Count vowels
vowels = "aeiou"
count = sum(1 for ch in s if ch in vowels)
print("Total vowels:", count)
# Check palindrome
if s == s[::-1]:
print(s, "is a Palindrome")
else:
print(s, "is NOT a Palindrome")
Enter a string: madam
Total vowels: 2
madam is a Palindrome
Enter a string: hello
Total vowels: 2
hello is NOT a Palindrome
Q.17 — Option B: Mutable/Immutable + Second Largest5 Marks
(a-i) Mutable vs Immutable
Mutable = can be changed after creation. Example: L=[1,2,3]; L[0]=10 → L=[10,2,3] ✅
Immutable = cannot be changed. Example: T=(1,2,3); T[0]=10 → TypeError
Mutable types: List, Dictionary, Set | Immutable: Integer, Float, String, Tuple
(a-ii) Type Conversion
- Implicit: Python automatically converts —
x = 5 + 2.0 → x = 7.0 (int auto-promoted to float)
- Explicit: Programmer manually converts —
x = int("42") → x = 42 (string to int)
(a-iii) is / is not vs ==
== checks value equality — are the values same ?
is checks identity — do they point to the same object in memory ?
a = [1,2]; b = [1,2]
print(a == b) # True — same values
print(a is b) # False — different objects in memory
(b) Second Largest without max()/sort() (2 Marks)
n = int(input("How many numbers? "))
lst = []
for i in range(n):
lst.append(int(input("Enter: ")))
first = second = float('-inf')
for num in lst:
if num > first:
second = first
first = num
elif num > second and num != first:
second = num
print("Second largest:", second)
List: [10, 45, 23, 67, 34]
Second largest: 45
Q.18 — NumPy Arrays — 1D, 2D, Operations 5 Marks
Q.18 — Complete NumPy Programs5 Marks
📊 Marking: Part (a) = 3 marks | Part (b) = 2 marks
(a) 1D → Reshape → Index (3 Marks)
import numpy as np
# (i) 1D array 1 to 20 using arange
arr = np.arange(1, 21)
print("Array:", arr)
print("Shape:", arr.shape) # (20,)
print("Size:", arr.size) # 20
print("Dtype:", arr.dtype) # int64
# (ii) Reshape to 4×5
arr2d = arr.reshape(4, 5)
print("\nReshaped 4×5 array:\n", arr2d)
# (iii) Indexing the 2D array
print("\nSecond row (index 1):", arr2d[1]) # [6 7 8 9 10]
print("Last column:", arr2d[:, -1]) # [ 5 10 15 20]
print("Element at [2][3] (0-based):", arr2d[2][3]) # 19
Array: [ 1 2 3 ... 20]
Shape: (20,) Size: 20 Dtype: int64
Reshaped 4×5 array:
[[ 1 2 3 4 5]
[ 6 7 8 9 10]
[11 12 13 14 15]
[16 17 18 19 20]]
Second row: [ 6 7 8 9 10]
Last column: [ 5 10 15 20]
Element at [2][3] = 14
(b) Array Operations — A and B (2 Marks)
import numpy as np
A = np.array([5, 10, 15, 20])
B = np.array([2, 4, 6, 8])
print("Element-wise sum:", A + B) # [7 14 21 28]
print("Element-wise product:", A * B) # [10 40 90 160]
C = np.concatenate((A, B))
print("Concatenated:", C) # [ 5 10 15 20 2 4 6 8]
print("Mean of C:", np.mean(C)) # 8.75
print("Std dev of A:", np.std(A)) # 5.59...
Element-wise sum: [ 7 14 21 28]
Element-wise product: [10 40 90 160]
Concatenated: [ 5 10 15 20 2 4 6 8]
Mean of C: 8.75
Std dev of A: 5.590169943749474
Q.19 — SQL Queries on PRODUCTS Table 5 Marks
Q.19 — Option A: All SQL Queries5 × 1 = 5
📊 Marking: 1 mark each correct query | Alternate correct syntax also accepted
(a) Electronics with price between 1000–20000
SELECT *
FROM PRODUCTS
WHERE CATEGORY = 'Electronics' AND PRICE BETWEEN 1000 AND 20000;
Result: Mobile (18000), Headphones (2500), Keyboard (1200)
(b) Most expensive product per category
SELECT CATEGORY, PNAME, MAX(PRICE) AS MAX_PRICE
FROM PRODUCTS
GROUP BY CATEGORY;
Electronics → Laptop 45000 | Furniture → Table 7500
(c) Products with 'a' anywhere in name
SELECT PNAME
FROM PRODUCTS
WHERE PNAME LIKE '%a%';
Result: Laptop, Chair, Table, Headphones, Keyboard
(d) Update Mobile price + increase Furniture stock
-- Update Mobile price
UPDATE PRODUCTS
SET PRICE = 20000
WHERE PNAME = 'Mobile';
-- Increase Furniture stock by 10
UPDATE PRODUCTS
SET STOCK = STOCK + 10
WHERE CATEGORY = 'Furniture';
(e) Total stock and average price per category
SELECT CATEGORY,
SUM(STOCK) AS TOTAL_STOCK,
AVG(PRICE) AS AVG_PRICE
FROM PRODUCTS
GROUP BY CATEGORY;
CATEGORY | TOTAL_STOCK | AVG_PRICE
Electronics | 205 | 17175.0
Furniture | 70 | 5500.0
💡 GROUP BY tip: Whenever you use aggregate functions (SUM, AVG, MAX, COUNT) with a non-aggregate column, you must use GROUP BY that column. Very common exam question.
Q.19 — Option B: CREATE DB + DDL + DML5 Marks
(a) Part (i)–(v) SQL Statements
-- (i) Create and use database
CREATE DATABASE SCHOOL;
USE SCHOOL;
-- (ii) Create TEACHER table
CREATE TABLE TEACHER (
TID INT PRIMARY KEY,
TNAME VARCHAR(40) NOT NULL,
SUBJECT VARCHAR(30),
SALARY FLOAT,
EXPERIENCE INT
);
-- (iii) Add column PHONE using ALTER
ALTER TABLE TEACHER ADD PHONE VARCHAR(15);
-- (iv) Drop column PHONE
ALTER TABLE TEACHER DROP COLUMN PHONE;
-- (v) Teachers with experience > 5, order by salary desc
SELECT TNAME, SALARY
FROM TEACHER
WHERE EXPERIENCE > 5
ORDER BY SALARY DESC;
(b) DDL vs DML (2 Marks)
| DDL — Data Definition Language | DML — Data Manipulation Language |
| Defines structure/schema of database | Manipulates data within the tables |
| Commands: CREATE, DROP, ALTER, TRUNCATE | Commands: INSERT, UPDATE, DELETE, SELECT |
| Cannot be rolled back easily | Can be rolled back (transactional) |
Q.20 — Python Functions + Dictionary 5 Marks
Q.20 — Complete Programs5 Marks
📊 Marking: Part (a) = 3 marks | Part (b) = 2 marks
(a) statistics_summary() — Mean, Median, Mode without module (3 Marks)
# Mean, Median, Mode — without statistics module
def statistics_summary(data):
n = len(data)
# Mean
mean = sum(data) / n
# Median
s = sorted(data)
mid = n // 2
median = s[mid] if n % 2 != 0 else (s[mid-1] + s[mid]) / 2
# Mode — element with highest frequency
freq = {}
for item in data:
freq[item] = freq.get(item, 0) + 1
mode = max(freq, key=freq.get)
return mean, median, mode
# Test with given data
data = [4, 8, 6, 5, 3, 8, 2, 8, 6, 4]
m, med, mod = statistics_summary(data)
print("Mean:", m)
print("Median:", med)
print("Mode:", mod)
Mean: 5.4
Median: 5.5
Mode: 8
Verification: Sum=54, n=10 → Mean=5.4 | Sorted=[2,3,4,4,5,6,6,8,8,8] → Median=(5+6)/2=5.5 | 8 appears 3 times → Mode=8 ✅
(b) Character Frequency of "RAJASTHAN" using while loop + dict (2 Marks)
s = "RAJASTHAN"
freq = {}
i = 0
while i < len(s):
ch = s[i]
if ch in freq:
freq[ch] += 1
else:
freq[ch] = 1
i += 1
for ch, count in freq.items():
print(ch, ":", count)
R : 1
A : 3
J : 1
S : 1
T : 1
H : 1
N : 1
Q.21 — NumPy 2D Operations + DBMS / Emerging Trends 5 Marks
Q.21 — Option A: NumPy 2D + Relational Model5 Marks
(a) 2D Array Operations (3 Marks)
import numpy as np
# (i) Create two 3×3 arrays
X = np.array([[1, 3, 5],
[2, 4, 6],
[7, 8, 9]])
Y = np.array([[9, 8, 7],
[6, 5, 4],
[3, 2, 1]])
# (ii) Matrix addition and element-wise product
print("X + Y:\n", X + Y)
print("X * Y (element-wise):\n", X * Y)
# (iii) Boolean indexing — elements > 5
print("Elements of X > 5:", X[X > 5])
# (iv) Statistics on X
print("Max:", np.max(X))
print("Min:", np.min(X))
print("Sum:", np.sum(X))
print("Mean:", np.mean(X))
print("Variance:", np.var(X))
X + Y:
[[10 11 12]
[ 8 9 10]
[10 10 10]]
X * Y (element-wise):
[[ 9 24 35]
[12 20 24]
[21 16 9]]
Elements of X > 5: [7 8 9]
Max: 9 Min: 1 Sum: 45 Mean: 5.0 Variance: 6.888...
(b) Relational Data Model Terms (2 Marks)
| Term | Definition | Example |
| Tuple | A single row/record in a table | One student's complete record |
| Attribute | A column representing a property | SID, SNAME, MARKS |
| Domain | Set of valid values an attribute can hold | MARKS domain: 0 to 100 (integer) |
| Primary Key | Attribute that uniquely identifies each tuple | SID in STUDENTS table |
| Foreign Key | Attribute referencing primary key of another table | SID in MARKS table → references STUDENTS.SID |
Q.21 — Option B: Emerging Trends + NumPy Random5 Marks
(a) Emerging Trends (3 Marks)
(i) Natural Language Processing (NLP): NLP is a branch of AI that enables computers to understand, interpret, and generate human language. Examples: Google Translate (translates between languages), Chatbots and virtual assistants (Siri, Alexa understand spoken commands).
(ii) Grid Computing vs Cloud Computing:
| Grid Computing | Cloud Computing |
| Distributed computing using multiple connected systems for one task | On-demand computing resources over the internet |
| Resources are heterogeneous and geographically dispersed | Centrally managed, scalable resources |
| Used for scientific computing (weather, genome research) | Used for web services, storage, apps (AWS, GCP) |
(iii) Smart Cities: Smart cities use technology to improve infrastructure, governance, and quality of life. Technologies: (1) IoT sensors for traffic management, (2) AI-based surveillance for security, (3) Cloud computing for centralised data management and government services.
(b) NumPy Random Array Program (2 Marks)
import numpy as np
# (i) Create array of 10 random integers between 1 and 50
arr = np.random.randint(1, 51, 10)
print("Array:", arr)
# (ii) Elements divisible by 5
print("Divisible by 5:", arr[arr % 5 == 0])
# (iii) Replace elements < 20 with 0
arr[arr < 20] = 0
print("Final array:", arr)
Array: [34 7 45 12 50 18 25 3 40 16]
Divisible by 5: [45 50 25 40]
Final array: [34 0 45 0 50 0 25 0 40 0]
💡 Boolean indexing: arr[arr % 5 == 0] — condition inside square brackets selects only elements satisfying the condition. arr[condition] = 0 replaces those elements. This is one of the most important NumPy exam topics.
Marking Scheme Summary
📊 Complete Marks DistributionTheory 70 Marks
| Section | Questions | Topics | Marks |
| A | Q.1–6 | MCQ + Fill Blanks + Match (Unit 1–5) | 20 |
| B | Q.7–16 | Computer System + Python + NumPy + SQL + Trends | 25 |
| C | Q.17–21 | Long Programs + Queries + DBMS concepts | 25 |
| Theory Total | 70 |
| Practical (Python 8 + NumPy 5 + SQL 5 + File 7 + Viva 5) | 30 |
| Grand Total | 100 |
💡 Score More — IP Golden Rules:
- SQL: Write all keywords in CAPITALS. Always end with semicolon. Mention column names explicitly —
SELECT * gets fewer marks than named columns.
- NumPy: Always write
import numpy as np first. Show output after each print statement if asked.
- Python: Indentation = 4 spaces. Write comments — examiners reward documented code.
- GROUP BY: Whenever aggregate function (SUM, AVG, MAX) is used with another column → GROUP BY is mandatory.
- LIKE operator:
% = any number of characters | _ = exactly one character. Very common in exam.
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